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Real Numbers — Class 10 Maths (Complete Chapter, Explained Step by Step)

Real Numbers — Class 10 Maths (Complete Chapter, Explained Step by Step)

Real Numbers is the perfect chapter to open Class 10 with — it is short, it is logical, and once two big ideas click into place, the marks almost take care of themselves. Don’t worry if primes and proofs feel intimidating right now. We are going to build everything from the ground up, one small step at a time, like a teacher sitting right beside you. Go at your own pace, and don’t move to the next part until the one you are on feels comfortable.

🎯 Try This
Pick any five house or shop numbers around you (like a phone number or a price tag). Check which ones are rational, and try writing two of them as a ratio p/q in lowest terms. (15 min)

Your Game Plan

  1. Warm up with what real numbers actually are.
  2. Learn the Fundamental Theorem of Arithmetic — the heart of this chapter.
  3. Use it to find HCF and LCM quickly and confidently.
  4. Master the one proof that appears almost every year — proving irrationality.
  5. Lock it in with the practice set at the end.

1. A Quick Warm-Up: What Are Real Numbers?

-2-10123√2 ≈ 1.41Rational: 1, ½, 0.75Irrational: √2, π, √3
Two families share one line — yellow rationals you can write as fractions, coral irrationals like √2 you cannot.

Every number you have ever used sits in one of two families. Rational numbers are the ones you can write as a fraction p/q (where q is not zero) — like 5, −3, 1/2, 0.75, or 0.333… . Irrational numbers are the ones you cannot write as a neat fraction — their decimals go on forever without repeating, like $\sqrt{2}$ = 1.41421356… or $\pi$ = 3.14159… . Put both families together and you get the real numbers — quite simply, every number you can mark as a point on the number line.

Key Idea
Real numbers = rational numbers + irrational numbers. If you can place it somewhere on the number line, it is a real number. This chapter is really about getting to know these two families better.

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2. The Fundamental Theorem of Arithmetic

primecomposite602302153560 = 2² × 3 × 5
Break any number into primes (yellow) until nothing splits further — there is only one way to do it.

Here is the big idea of the whole chapter. Every composite number can be broken down into a product of prime numbers — and, wonderfully, there is only one way to do it (apart from the order you write them in). Think of primes as the building blocks of numbers, like LEGO bricks: every number is built from primes in exactly one unique way. This is called the Fundamental Theorem of Arithmetic.

To find that prime “recipe” for a number, you keep dividing by the smallest prime that fits, again and again, until you are left with 1. Let’s do a few together.

Example 1 — Prime factorise 60
Start with the smallest prime, 2:  60 = 2 × 30.  Again: 30 = 2 × 15.  15 is not even, so move to 3: 15 = 3 × 5.  And 5 is prime. So 60 = 2 × 2 × 3 × 5 = 22 × 3 × 5.
Example 2 — Prime factorise 140
140 = 2 × 70 = 2 × 2 × 35 = 2 × 2 × 5 × 7. So 140 = 22 × 5 × 7.
Example 3 — Prime factorise 3825
3825 is not even, so try 5: 3825 = 5 × 765. Again 765 = 5 × 153. Now 153 = 3 × 51 = 3 × 3 × 17, and 17 is prime. So 3825 = 32 × 52 × 17.
Key Idea
The prime factorisation of a number is unique. No matter how you break it down, you always land on the same set of primes. That uniqueness is what makes everything else in this chapter work.
Common Mistake
1 is not a prime number, so it never appears in a prime factorisation. And always write repeated primes as powers (22, not 2 × 2) — it makes the next step, HCF and LCM, far easier.

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3. Finding HCF and LCM the Smart Way

Once you have the prime factorisations, HCF and LCM become almost mechanical. Here are the two rules — learn them by heart:

Key Rule
HCF = multiply the smallest power of each prime that is common to all the numbers.
LCM = multiply the greatest power of every prime that appears in any of the numbers.
Example 1 — HCF and LCM of 96 and 404
96 = 25 × 3  and  404 = 22 × 101.
Common prime is only 2; its smallest power is 22, so HCF = 22 = 4.
For LCM, take the greatest power of every prime: 25 × 3 × 101 = LCM = 9696.
Example 2 — HCF and LCM of 6, 72 and 120
6 = 2 × 3,  72 = 23 × 32,  120 = 23 × 3 × 5.
Common to all three: 2 (smallest power 21) and 3 (smallest power 31) → HCF = 2 × 3 = 6.
Greatest power of every prime: 23 × 32 × 5 = LCM = 360.

There is also a lovely shortcut that works for exactly two numbers:

Key Rule
For any two numbers a and b:  HCF × LCM = a × b.  So if you know three of these four values, you can always find the fourth.
Example 3 — Check the shortcut
For 96 and 404: HCF × LCM = 4 × 9696 = 38784, and 96 × 404 = 38784. They match — as they always will.
Example 4 — Find the missing number
The HCF of two numbers is 9 and their LCM is 90. If one number is 18, find the other.
Other number $= (HCF \times LCM) \div (\text{one number}) = (9 \times 90) \div 18 = 810 \div 18 =$ 45.
Example 5 — A real-life LCM problem
Two bells ring at intervals of 12 and 15 minutes. If they ring together at 9:00 am, when will they next ring together?
They meet again after LCM(12, 15) = 60 minutes. So the next time is 10:00 am.
Common Mistake
The shortcut HCF × LCM = product works only for two numbers. For three or more, always go back to the prime-factorisation rules.
Exam Tip
Whenever a question mixes “earliest time they meet again”, “largest tile that fits exactly”, or “maximum students per row”, it is secretly an LCM or HCF question. “Largest / maximum that divides” → HCF. “Earliest / next time / smallest common” → LCM.

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4. Proving a Number Is Irrational

This is the part students fear the most — and it is actually the most predictable, because the same proof appears almost every year. We use a clever, backwards method called proof by contradiction: we pretend the number is rational, follow the logic honestly, and watch it crash into something impossible. Since our pretence breaks mathematics, the number cannot be rational — so it must be irrational. Let’s walk through the classic proof slowly.

The proof that $\sqrt{2}$ is irrational
Step 1. Suppose, just for argument, that $\sqrt{2}$ is rational. Then we could write $\sqrt{2}$ = p/q, where p and q are integers with no common factor (the fraction is in lowest terms) and q ≠ 0.
Step 2. Square both sides: 2 = p2/q2, so p2 = 2q2. This means p2 is even, and if p2 is even then p itself is even. So write p = 2m.
Step 3. Substitute: (2m)2 = 2q2 → 4m2 = 2q2 → q2 = 2m2. So q2 is even, which means q is even too.
Step 4. But now both p and q are even — they share a common factor of 2. That contradicts Step 1, where we said they had no common factor. The pretence has broken. Therefore $\sqrt{2}$ cannot be rational, so $\sqrt{2}$ is irrational.

The beautiful thing is that $\sqrt{3}$ and $\sqrt{5}$ are proved in exactly the same four steps — just replace 2 with 3 or 5. Learn the flow once and you own all of them.

Example — Prove that 3 + 2$\sqrt{5}$ is irrational
Suppose 3 + 2$\sqrt{5}$ is rational. Then 2$\sqrt{5}$ = (that rational number) − 3, which is still rational. Dividing a rational by 2 keeps it rational, so $\sqrt{5}$ would be rational. But we know $\sqrt{5}$ is irrational — a contradiction. Hence 3 + 2$\sqrt{5}$ is irrational. (A rational number plus or times an irrational one is always irrational.)
Common Mistake
You must state at the start that p and q have no common factor (are coprime / in lowest terms). The entire contradiction depends on it — leave it out and the proof earns no marks.
Exam Tip
This proof is near-guaranteed in the board paper. Memorise the flow — assume rational and coprime → square → show p even → show q even → contradiction — not the exact words. Then you can reproduce it for $\sqrt{2}$, $\sqrt{3}$ or $\sqrt{5}$ under any pressure.

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Practice Worksheet

Try each question fully on paper first, then tap Show Answer to check yourself.

Q1. Express 3825 as a product of its prime factors.

Show Answer
3825 = 5 × 765 = 5 × 5 × 153 = 5 × 5 × 3 × 51 = 52 × 3 × 3 × 17 = 32 × 52 × 17.

Q2. Find the HCF and LCM of 90 and 144 by prime factorisation, and verify HCF × LCM = product of the numbers.

Show Answer
90 = 2 × 32 × 5,  144 = 24 × 32. HCF = 2 × 32 = 18; LCM = 24 × 32 × 5 = 720. Check: 18 × 720 = 12960 = 90 × 144. ✓

Q3. The HCF of two numbers is 12 and their LCM is 240. If one number is 48, find the other.

Show Answer
Other $= (HCF \times LCM) \div (\text{one number}) = (12 \times 240) \div 48 = 2880 \div 48 =$ 60.

Q4. Two bells toll at intervals of 9 and 12 minutes. If they toll together at 6:00 am, when will they next toll together?

Show Answer
They meet again after LCM(9, 12) = 36 minutes, i.e. at 6:36 am.

Q5. Prove that $\sqrt{3}$ is irrational.

Show Answer
Suppose $\sqrt{3}$ = p/q with p, q coprime, q ≠ 0. Then 3 = p2/q2 → p2 = 3q2, so p2 is divisible by 3, hence p is divisible by 3. Write p = 3m: 9m2 = 3q2 → q2 = 3m2, so q is also divisible by 3. Then p and q share the factor 3 — contradicting “coprime”. Hence $\sqrt{3}$ is irrational.

Q6. Prove that 5 − $\sqrt{3}$ is irrational.

Show Answer
Suppose 5 − $\sqrt{3}$ is rational. Then $\sqrt{3}$ = 5 − (that rational number), which would be rational. But $\sqrt{3}$ is irrational (Q5) — a contradiction. Hence 5 − $\sqrt{3}$ is irrational.

Once these feel easy, you have genuinely mastered Real Numbers. Don’t aim for perfect on the first try — aim for one more correct question than yesterday.

⚡ Quick Quiz — Test Yourself
Tap an option to check instantly. Six questions — no peeking at the notes!

1. What is the HCF of 96 and 404?

96 = 2⁵ × 3 and 404 = 2² × 101. The only common prime is 2, and its smallest power is 2² = 4.

2. What is the LCM of 6, 72 and 120?

6 = 2×3, 72 = 2³×3², 120 = 2³×3×5. Take the greatest power of every prime: 2³ × 3² × 5 = 360.

3. Which of these is an irrational number?

0.75, 22/7 and 3.14 can all be written as fractions. √2 = 1.41421356… never terminates or repeats, so it is irrational.

4. HCF of two numbers is 9 and their LCM is 90. If one number is 18, the other is:

Product of two numbers = HCF × LCM. So other = (9 × 90) ÷ 18 = 810 ÷ 18 = 45.

5. The Fundamental Theorem of Arithmetic says the prime factorisation of a composite number is:

Every composite number can be written as a product of primes in exactly one way, apart from the order of the factors.

6. 3825 written as a product of primes is:

3825 ÷ 25 = 153, and 153 = 9 × 17 = 3² × 17. So 3825 = 3² × 5² × 17. (153 and 425 are not primes, so those options are not fully factorised.)

Written & reviewed by Team Principal Saab — Meet the team →